ISRO Mechanical & Aerospace 2018 Question Paper & Solutions

Attempt the ISRO Mechanical & Aerospace 2018 previous year paper in real CBT exam mode or practice mode with verified answers and explanations.

All ISRO Mechanical & Aerospace papers

80 questions. Answers are shown only where the official answer key is available.

Question 1

Topic: Thermodynamics

The pressure P of a gas in terms of its mean kinetic energy per unit volume E is equal to

  • A. E/3
  • B. E/2
  • C. 3E/4
  • D. 2E/3

Answer: D. 2E/3

Explanation: Kinetic energy for gas KE = (3/2)RT = (3/2)PV. Therefore, KE/V = (3/2)P = E, which means P = (2/3)E.

Question 2

Topic: Thermodynamics

Work done in a free expansion process is

  • A. +ve
  • B. -ve
  • C. zero
  • D. none of the above

Answer: C. zero

Explanation: The work done in a free expansion process is zero because free expansion is an irreversible adiabatic and isentropic process. In free expansion, there is no external resistance upon which system can apply force.

Question 3

Topic: Thermodynamics

If the value of n is infinitely large in a polytropic process PV^n=C, then the process is known as constant

  • A. volume
  • B. pressure
  • C. temperature
  • D. entropy

Answer: A. volume

Explanation: PV^n = C can be written as P^(1/n) * V = C^(1/n). If n is infinity, then 1/n approaches 0, leaving V = Constant (C). This is a constant volume process.

Question 4

Topic: Thermodynamics

During the charging of a storage battery, the current I is 20A and the voltage E in 12.8V. The ratio of heat transfer from the battery is 16W. At what rate is the internal energy increasing?

  • A. 256 Js^-1
  • B. 272 Js^-1
  • C. 0
  • D. 240 Js^-1

Answer: D. 240 Js^-1

Explanation: Energy stored in battery during charging = (V * I) - Q = (12.8 * 20) - 16 = 256 - 16 = 240 W (or Js^-1).

Question 5

Topic: IC Engines

The compression ratio for diesel engines is close to

  • A. 3 to 6
  • B. 5 to 8
  • C. 15 to 20
  • D. 20 to 30

Answer: C. 15 to 20

Explanation: For diesel engine compression ratio rc = 15-22. For Otto engine rc = 7-12. For Dual cycle engine rc = 13-17.

Question 6

Topic: Thermodynamics

One kg of carbon monoxide requires how much quantity of oxygen to produce 11/7 kg of carbon dioxide gas?

  • A. 4/7 kg
  • B. 11/4 kg
  • C. 9/7 kg
  • D. None of the above

Answer: A. 4/7 kg

Explanation: CO + 0.5 O2 -> CO2. 1/2 mole of O2 would make 1 mole CO2. So, 16 kg O2 would make 44 kg CO2. Then (16/44) kg O2 would make 1 kg CO2. Therefore, 11/7 kg CO2 is made by (11/7) * (16/44) kg O2 = 4/7 kg O2.

Question 7

Topic: Thermodynamics

The entropy of water at 0 K is assumed to be

  • A. 1 JK^-1
  • B. -1 JK^-1
  • C. 10 JK^-1
  • D. 0

Answer: D. 0

Explanation: The entropy of water at 0 K is assumed to be zero.

Question 8

Topic: Thermodynamics

An expression process as per law PV = constant is known as

  • A. parabolic expansion
  • B. hyperbolic expansion
  • C. isentropic expansion
  • D. free expansion

Answer: B. hyperbolic expansion

Explanation: We know that PV = nRT = constant. For a constant number of moles, temperature is constant. In a P-V diagram, this represents a hyperbolic curve.

Question 9

Topic: Fluid Mechanics

Speed of an aeroplane is measured by

  • A. pitot tube
  • B. hot wire anemometer
  • C. venturimeter
  • D. rotameter

Answer: A. pitot tube

Explanation: Pitot tube is used to measure the velocity of airplanes and boats. Hot Wire Anemometer measures fluid velocity, Venturi meter measures flow rate, and Rotameter measures volumetric flow rate.

Question 10

Topic: Fluid Mechanics

Euler's dimensionless number relates the following

  • A. inertial force and gravity
  • B. viscous force and inertial force
  • C. pressure force and inertial force
  • D. viscous force and pressure force

Answer: C. pressure force and inertial force

Explanation: Euler Number (Eu) is defined as the ratio of Inertial Force to Pressure Force, i.e., $\sqrt{Fi / Fp}$.

Question 11

Topic: Fluid Mechanics

Speed of sound in water is equal to (K-bulk modulus, p-density)

  • A. $\sqrt{K/p}$
  • B. $\sqrt{K*p}$
  • C. $\sqrt{p/K}$
  • D. K/p

Answer: A. $\sqrt{K/p}$

Explanation: Speed of sound in water is C = $\sqrt{K/p}$, where K is Bulk modulus and p is Density.

Question 12

Topic: Fluid Mechanics

For an irrotational flow, d²(phi)/dx² + d²(phi)/dy² = 0 is the equation given by

  • A. Cauchy-Riemann
  • B. Reynolds
  • C. Laplace
  • D. Bernoulli

Answer: C. Laplace

Explanation: The expression d²(phi)/dx² + d²(phi)/dy² = 0 is known as the Laplace equation.

Question 13

Topic: Thermodynamics

A simple compressible substance inside a cylinder undergoes a change of state quasistatically, isothermally and at constant pressure of 1.5 MPa. If the enthalpy change for the system is 4000 kJ at 150 °C, what is the corresponding change in its entropy?

  • A. 9.45 kJ K^-1
  • B. 26.67 kJ K^-1
  • C. 14.17 kJ K^-1
  • D. 0

Answer: A. 9.45 kJ K^-1

Explanation: Since it is a phase change (temperature is constant), we use dH = TdS + VdP. At constant pressure (dP = 0), dH = TdS. Entropy change dS = dH / T = 4000 / (150 + 273) = 9.45 kJ/K.

Question 14

Topic: Fluid Mechanics

The velocity of sound in a gaseous medium at a temperature of 400K is 400 ms^-1. If the temperature of the medium is increased to 600 K, the velocity of sound will be nearly

  • A. 400 ms^-1
  • B. 490 ms^-1
  • C. 600 ms^-1
  • D. None of there

Answer: B. 490 ms^-1

Explanation: Velocity of sound in a gaseous medium C = $\sqrt{gamma * R * T}$. Thus, C is proportional to $\sqrt{T}$. C2 = C1 * $\sqrt{T2/T1}$ = 400 * $\sqrt{600/400}$ = 489.89, which is approximately 490 m/s.

Question 15

Topic: Fluid Mechanics

Stress strain relation of the Newtonian fluid is

  • A. parabolic
  • B. linear
  • C. hyperbolic
  • D. inverse type

Answer: B. linear

Explanation: The stress-strain relation of a Newtonian fluid is linear, meaning the shear stress is directly proportional to the rate of shear strain.

Question 16

Topic: Fluid Machinery

In a centrifugal pump casing, the flow of water leaving the impeller is

  • A. rectilinear flow
  • B. free vortex motion
  • C. radial flow
  • D. forced vortex

Answer: B. free vortex motion

Explanation: Flow inside the impeller of centrifugal pump is forced vortex motion and the flow of water leaving the impeller is free vortex motion.

Question 17

Topic: Thermodynamics

For a two stage reciprocating compressor, compression from P1 to P3 is with perfect inter cooling and no pressure losses. If compression in both the cylinders follows the same polytropic process and the atmospheric pressure is Pa, then the intermediate pressure P2 is given by

  • A. P2 = (P1 + P3) / Pa
  • B. P2 = $\sqrt{P1 * P3}$
  • C. P2 = Pa * $\sqrt{P3 / P1}$
  • D. P2 = Pa * $\sqrt{P1 / P3}$

Answer: B. P2 = $\sqrt{P1 * P3}$

Explanation: For perfect inter-cooling, intermediate pressure P2 is the geometric mean of initial and final pressures: P2 = $\sqrt{P1 * P3}$.

Question 18

Topic: Fluid Machinery

The degree of reaction in an axial flow compressor is defined as the ratio of static enthalpy rise in the

  • A. rotor to static enthalpy rise in the stator
  • B. stator to static enthalpy rise in the rotor
  • C. rotor to static enthalpy rise in the stage
  • D. stator to static enthalpy rise in the stage

Answer: C. rotor to static enthalpy rise in the stage

Explanation: The degree of reaction in an axial flow compressor is defined as the ratio of static enthalpy rise in the rotor to static enthalpy rise in the stage.

Question 19

Topic: Engineering Physics

The frequency of ultrasonic waves is

  • A. less than 20 Hz
  • B. between 20 to 10000 Hz
  • C. between 20 to 20000 Hz
  • D. above 20000 Hz

Answer: D. above 20000 Hz

Explanation: Range of frequency of waves: Infrasonic <= 20 Hz, Sonic 20 Hz to 20 kHz, Ultrasonic > 20 kHz.

Question 20

Topic: Engineering Physics

Loudness of the sound does not change with the change in

  • A. frequency
  • B. amplitude
  • C. distance from the source of sound
  • D. none of these

Answer: A. frequency

Explanation: Loudness refers to how loud or soft a sound feels to a listener. The loudness of sound is determined by the intensity of the sound waves and does not change with a change in frequency.

Question 21

Topic: Fluid Mechanics

If the stream function of two dimensional flow is psi = 5xy, then the velocity at a point (3, 4) is

  • A. 25 m/s
  • B. 20 m/s
  • C. 7 m/s
  • D. 5 m/s

Answer: A. 25 m/s

Explanation: Velocity in x-direction U = d(psi)/dy = 5x -> U(3,4) = 15 m/s. Velocity in y-direction V = -d(psi)/dx = -5y -> V(3,4) = -20 m/s. Resultant velocity V' = $\sqrt{U² + V²}$ = $\sqrt{15^2 + (-20}$^2) = 25 m/s.

Question 22

Topic: Fluid Mechanics

A glass tube of 8 mm diameter is immersed in water. Surface tension of water is 0.0075 kg m and rise of water in the tube due to capillary effect is

  • A. 7.5 mm
  • B. 3.75 mm
  • C. 11.25 mm
  • D. None of these

Answer: B. 3.75 mm

Explanation: Rise of water in the tube due to capillary effect h = (4 * sigma * cos(theta)) / (rho * g * d). For water in glass tube theta = 0, cos(0) = 1. h = (4 * 0.0075 * 1) / (1000 * 0.008) = 0.00375 m = 3.75 mm.

Question 23

Topic: Fluid Machinery

An impulse turbine produces 125 hp under a head of 25 meters. By what percentage should the speed be increased for a head of 100 metres

  • A. 25%
  • B. 50%
  • C. 75%
  • D. 100%

Answer: D. 100%

Explanation: Unit speed of turbine is N1/$\sqrt{H1}$ = N2/$\sqrt{H2}$. So, N1/$\sqrt{25}$ = N2/$\sqrt{100}$, meaning N2 = 2*N1. The speed should be increased by 100%.

Question 24

Topic: Fluid Machinery

The specific speed of a centrifugal pump, delivering 1000 litres of water per second against a head of 16 metre at 800 rpm

  • A. 50 rpm
  • B. 100 rpm
  • C. 150 rpm
  • D. 200 rpm

Answer: B. 100 rpm

Explanation: Specific speed of centrifugal pump Ns = N*$\sqrt{Q}$ / H^(3/4) = 800 * $\sqrt{1000 * 10^-3}$ / 16^(3/4) = 100 rpm.

Question 25

Topic: Fluid Mechanics

A pipe of 0.1 m² suddenly changes to 0.5 m² area. The quantity of water flowing in the pipe is 0.5 m³/s. Head loss due to sudden enlargement is nearly

  • A. 0.025 m
  • B. 0.05 m
  • C. 0.8 m
  • D. 1.2 m

Answer: C. 0.8 m

Explanation: V1 = Q/A1 = 0.5/0.1 = 5 m/s. V2 = Q/A2 = 0.5/0.5 = 1 m/s. Head loss due to sudden enlargement h = (V1 - V2)^2 / 2g = (5 - 1)^2 / 20 = 16 / 20 = 0.8 m.

Question 26

Topic: Fluid Machinery

Efficiency of a centrifugal pump is maximum when the blades are

  • A. straight
  • B. forward curved
  • C. backward curved
  • D. forward and backward curved

Answer: C. backward curved

Explanation: When the blades of a centrifugal pump are backward curved, the efficiency is maximum.

Question 27

Topic: Fluid Mechanics

The hydraulic diameter, Dh of a rectangular channel with sides 'a' and 'b' is,

Figure for question 27, ISRO Mechanical & Aerospace 2018

  • A. Dh = 2ab / (a+b)
  • B. Dh = 4ab / (2a+b)
  • C. Dh = 2ab / (2a+b)
  • D. Dh = 4ab / (a+b)

Answer: A. Dh = 2ab / (a+b)

Explanation: Hydraulic diameter Dh = 4 * Area / Perimeter = 4(ab) / 2(a+b) = 2ab / (a+b).

Question 28

Topic: Heat Transfer

Which of the following has maximum value of thermal conductivity?

  • A. steel
  • B. copper
  • C. brass
  • D. aluminium

Answer: B. copper

Explanation: Copper has a thermal conductivity of ~385 W/mK, Aluminium is ~210 W/mK, Brass is ~110 W/mK, and Steel is 35-55 W/mK. Copper is the highest among the options.

Question 29

Topic: Heat Transfer

A steam pipe is to be insulated by 2 insulating materials put over each other. For best results

  • A. better insulation should be put over pipe and inferior one over it
  • B. inferior insulation should be put over pipe and better one over it
  • C. both may put in any order
  • D. unpredictable

Answer: D. unpredictable

Explanation: In case of same thickness of insulation, for better insulation K1 < K2 (better insulation over pipe). However, since the thickness of insulation is not given in the question, the result is unpredictable.

Question 30

Topic: Heat Transfer

The value of Biot number is very small (<0.01) when

  • A. conductive resistance of the fluid is negligible
  • B. conductive resistance within the body is negligible
  • C. conductive resistance of the fluid surface of the body is negligible
  • D. None of these

Answer: B. conductive resistance within the body is negligible

Explanation: The value of Biot number is very small when the conductive resistance within the body is negligible (meaning its internal conductivity approaches infinity).

Question 31

Topic: Heat Transfer

The critical radius of insulation for a spherical shell is

  • A. thermal conductivity of insulating material / heat transfer coefficient at the outer surface
  • B. 2 x thermal conductivity of insulating material / heat transfer coefficient at the outer surface
  • C. thermal conductivity of insulating material / 2 x heat transfer coefficient at the outer surface
  • D. heat transfer coefficient at the outer surface / thermal conductivity of insulating material

Answer: B. 2 x thermal conductivity of insulating material / heat transfer coefficient at the outer surface

Explanation: Critical radius of insulation rc = 2K/h for a spherical shell, whereas rc = K/h for a cylindrical shell.

Question 32

Topic: Heat Transfer

If the temperature of a solid surface changes from 27 °C to 81 °C, then its emissive power changes in the ratio of nearly

  • A. 81
  • B. 9
  • C. 1.49
  • D. 1.94

Answer: D. 1.94

Explanation: Emissive Power (E) is proportional to T^4. E2/E1 = (T2/T1)^4 = ((81+273)/(27+273))^4 = (354/300)^4 = 1.938, which is approximately 1.94.

Question 33

Topic: Refrigeration and Air Conditioning

The heat removal rate from a refrigerated space is 7.2 kW and the power input to the compressor is 1.8 kW. The coefficient of performance (COP) of the refrigerator is

  • A. 4
  • B. 5
  • C. 1.25
  • D. 0.25

Answer: A. 4

Explanation: COP of refrigerator = Heat removed from space / Work done = 7.2 / 1.8 = 4.

Question 34

Topic: Heat Transfer

For a fluid having Prandtl number equal to unity, the relation between hydrodynamic boundary layer thickness (delta_1) and thermal boundary layer thickness (delta_2) is

  • A. delta_1 > delta_2
  • B. delta_1 < delta_2
  • C. delta_1 = delta_2
  • D. delta_2 = delta_1 / 3

Answer: C. delta_1 = delta_2

Explanation: The relationship is given by Pr^(1/3) = delta_1 / delta_2. If Pr = 1, then delta_1 = delta_2.

Question 35

Topic: Machine Design

Life of a ball bearing at a load of 10 kN is 24000 hours. If the load is increased to 20 kN (all other conditions are same), its life in hour is

  • A. 1000 h
  • B. 3000 h
  • C. 6000 h
  • D. 12000 h

Answer: B. 3000 h

Explanation: Life L = (C/P)^n. For ball bearing n = 3, so L is proportional to 1/P³. L2/L1 = (P1/P2)^3. L2 = 24000 * (10/20)^3 = 24000 * (1/8) = 3000 hours.

Question 36

Topic: Manufacturing

The main objective of 'shot peening' is to improve which property of metal parts

  • A. fatigue strength
  • B. ductility
  • C. surface finish
  • D. none of these

Answer: A. fatigue strength

Explanation: Shot peening is a cold working process used to finish metal parts to prevent failure by improving fatigue strength.

Question 37

Topic: Metrology

A hole is of dimension phi 60 (+0.015 / +0.000) and the corresponding shaft is of dimension phi 60 (+0.011 / +0.001). When they are assembled they will form a

  • A. interference fit
  • B. clearance fit
  • C. transition fit
  • D. none of these

Answer: C. transition fit

Explanation: Upper size of hole = 60.015 mm. Upper size of shaft = 60.011 mm. The upper size of the shaft is more than the lower size of the hole (60mm) but less than the upper size of the hole. So the assembled parts make a transition fit.

Question 38

Topic: Manufacturing

Which of the following carbon steels is most weldable

  • A. 1.0% carbon steel
  • B. 0.3% carbon steel
  • C. 0.5% carbon steel
  • D. 0.15% carbon steel

Answer: D. 0.15% carbon steel

Explanation: Low carbon steel (0.15% carbon) is most weldable among them because they can be welded with low preheat and no post-treatment is required.

Question 39

Topic: Material Science

A small percentage of boron is added to steel in order to

  • A. increase endurance strength
  • B. reduce machinability
  • C. increase water resistance
  • D. increase hardenability

Answer: D. increase hardenability

Explanation: Boron gives hardness to steel. So, a small percentage of boron is added to steel in order to increase hardenability.

Question 40

Topic: Strength of Materials

A material that exhibits the same elastic properties in all directions at a point is called

  • A. homogenous
  • B. heterogenous
  • C. isotropic
  • D. orthotropic

Answer: C. isotropic

Explanation: A material that exhibits the same elastic properties in all directions at a given point is called isotropic.

Question 41

Topic: Material Science

Number of atoms per unit cell of a face centered cubic (FCC) lattice is

  • A. 14
  • B. 7
  • C. 4
  • D. 10

Answer: C. 4

Explanation: Number of atoms per unit cell for crystal systems: SC is 1, BCC is 2, and FCC is 4.

Question 42

Topic: Material Science

The impact strength of a material is an index of its

  • A. fatigue strength
  • B. tensile strength
  • C. hardness
  • D. toughness

Answer: D. toughness

Explanation: The impact strength is the resistance of a material to fracture under a sudden impact or shock load, it is a measure of the toughness of the material.

Question 43

Topic: Material Science

Which of the following order of crystal structure will match with metals Iron - Nickel - Titanium in that order at room temperature?

  • A. BCC-HCP-FCC
  • B. FCC-BCC-HCP
  • C. HCP-FCC-BCC
  • D. BCC-FCC-HCP

Answer: D. BCC-FCC-HCP

Explanation: Iron is BCC, Nickel is FCC, and Titanium is HCP at room temperature.

Question 44

Topic: Manufacturing

In a machining operation cutting speed is reduced by 50%. Assuming n = 0.5, C = 300 in Taylor's equation, the increase in tool life is

  • A. 2
  • B. 4
  • C. 8
  • D. 16

Answer: B. 4

Explanation: Taylor's equation is VT^n = C. V1(T1)^0.5 = V2(T2)^0.5 => V(T1)^0.5 = (V/2)(T2)^0.5 => (T2/T1)^0.5 = 2 => T2 = 4*T1. The tool life increases by a factor of 4.

Question 45

Topic: Manufacturing

In a linear arc welding process, the heat input per unit length is inversely proportional to

  • A. welding current
  • B. welding speed
  • C. welding voltage
  • D. duty cycle of power source

Answer: B. welding speed

Explanation: In a linear arc welding process, the heat input per unit length is inversely proportional to welding speed. As we increase welding speed, heat input per unit length decreases due to less time available for heat transfer.

Question 46

Topic: Manufacturing

The welding process which uses a blanket of fusible granular flux is

  • A. submerged arc welding
  • B. tungsten inert gas welding
  • C. electroslag welding
  • D. thermit welding

Answer: A. submerged arc welding

Explanation: In submerged arc welding, a blanket of fusible granular flux is used to shield the weld zone.

Question 47

Topic: Manufacturing

In a metal sheet of 3 mm thickness, a hole of 7mm diameter needs to be punched. The yield strength in tension of the sheet material is 120 MPa and its ultimate shear strength is 100 MPa. The force required to punch the hole is

  • A. 7.92 kN
  • B. 11.6 kN
  • C. 6.6 kN
  • D. 13.9 kN

Answer: C. 6.6 kN

Explanation: Punching force F = pi * D * t * tau_s = 3.14 * 7 * 3 * 100 = 6594 N = 6.594 kN (approximately 6.6 kN).

Question 48

Topic: Metrology

Profile of a gear tooth can be checked by

  • A. sine bar
  • B. bench micrometer
  • C. optical pyrometer
  • D. optical projector

Answer: D. optical projector

Explanation: Profile of a gear tooth can be checked by an optical projector.

Question 49

Topic: Metrology

The reflector combined with auto collimator can be used for checking

  • A. parallelism
  • B. circularity
  • C. surface finish
  • D. alignment

Answer: D. alignment

Explanation: Auto-Collimator is an instrument used to measure small angular inclinations. It is also used to check straightness, flatness and alignment.

Question 50

Topic: Industrial Engineering

PERT has following time estimate

  • A. one time estimate
  • B. two time estimate
  • C. three time estimate
  • D. nil time estimate

Answer: C. three time estimate

Explanation: PERT uses three time estimates: Optimistic time estimate, Pessimistic time estimate, and Most likely time estimate.

Question 51

Topic: Material Science

Which of the following is an amorphous material

  • A. mica
  • B. lead
  • C. rubber
  • D. glass

Answer: D. glass

Explanation: Amorphous solids are non-crystalline solids in which the atoms and molecules are not organized in a definite lattice pattern. Such solids include glass, gel, etc.

Question 52

Topic: Engineering Mathematics

In a party, each person shake hands with every other person present. The total number of handshakes was 45. The number of people in the party is

  • A. 12
  • B. 10
  • C. 8
  • D. 6

Answer: B. 10

Explanation: Total number of handshakes for n people is nC2 = n(n-1)/2. So, n(n-1)/2 = 45 => n² - n - 90 = 0. Solving gives n = 10.

Question 53

Topic: Engineering Mathematics

Two non-zero vectors are parallel if their vector product is

  • A. 1
  • B. 0
  • C. -1
  • D. infinity

Answer: B. 0

Explanation: Vector product is |a||b|sin(theta). Two non-zero vectors are parallel if the angle between them is zero degrees, making sin(0) = 0, thus their vector product is zero.

Question 54

Topic: Engineering Mathematics

If Eigen value a matrix A is lambda, then the Eigen value of A² is

  • A. 1
  • B. 1/lambda
  • C. 1/lambda²
  • D. lambda²

Answer: D. lambda²

Explanation: If the Eigen value of a matrix A is lambda, then the Eigen value of A² is lambda².

Question 55

Topic: Engineering Mathematics

The value of lim(x->infinity) (sin x) / x is equal to

  • A. 1
  • B. -1
  • C. Infinity
  • D. zero

Answer: D. zero

Explanation: The value of lim(x->infinity) (sin x) / x = 0 since sin(x) is bounded between -1 and 1, and dividing by infinity yields zero.

Question 56

Topic: Engineering Mathematics

If f(x) = (1-x)/(1+x) then f(1/x) is equal to

  • A. f(x)
  • B. f(x)
  • C. f(-x)
  • D. +/- f(x)

Explanation: Replacing x with 1/x: f(1/x) = (1 - 1/x)/(1 + 1/x) = (x - 1)/(x + 1) = -((1 - x)/(1 + x)) = -f(x).

Question 57

Topic: Engineering Mathematics

Inverse Laplace transform of [question incomplete in source,cite: 2]

  • A. (e^at + e^-at)/2
  • B. s/(s²+a²) i
  • C. (e^at)/2
  • D. (e^-at)/2

Explanation: This question was deleted or marked with no answer provided by ISRO due to an incomplete question statement.

Question 58

Topic: Engineering Mathematics

One dimensional wave equation is

  • A. d^2y/dt² = a²(d^2y/dx²)
  • B. dy/dt = alpha²(d^2y/dx²)
  • C. d^2y/dt² + d^2y/dx² = 0
  • D. none of these

Answer: A. d^2y/dt² = a²(d^2y/dx²)

Explanation: The wave equation is d^2y/dt² = a²(d^2y/dx²). Option (b) is the heat equation, and (c) is the Laplace equation.

Question 59

Topic: Engineering Mathematics

Which of the following method is said to be a direct method in numerical methods?

  • A. Regula-Falsi method
  • B. Gauss-Siedel method
  • C. Newton-Raphson method
  • D. Gauss elimination method

Answer: D. Gauss elimination method

Explanation: Gauss elimination method is a direct method for solving a linear system of equations whereas the other options are iterative methods.

Question 60

Topic: Engineering Mathematics

If X is a normal variable with mean mu and standard deviation sigma, then the mean and standard deviation of the variable Z = (X - mu)/sigma is

  • A. 1 and 0 respectively
  • B. mu and sigma respectively
  • C. 0 and 1 respectively
  • D. None of these

Answer: C. 0 and 1 respectively

Explanation: For a standard normal variable Z = (X - mu)/sigma, the mean is 0 and the standard deviation is 1.

Question 61

Topic: Engineering Mathematics

Example for an elliptic partial differential equation is

  • A. U_xx + U_yy = 0
  • B. U_t = c² * U_xx
  • C. U_tt = c² * U_yy
  • D. yU_xx + U_yy = 0

Answer: A. U_xx + U_yy = 0

Explanation: U_xx + U_yy = 0 represents the Laplace equation, which is a classic example of a second order linear elliptic partial differential equation.

Question 62

Topic: Engineering Mathematics

The solution of the equation y'' + y = 0 satisfy the condition y(0) = 1, y(pi/2) = 2, is

  • A. cos x + 2 sin x
  • B. cos x + sin x
  • C. 2 cos x + sin x
  • D. 2(cos x + 2 sin x)

Answer: A. cos x + 2 sin x

Explanation: The general solution is y = C1*sin(x) + C2*cos(x). Using y(0) = 1 gives C2 = 1. Using y(pi/2) = 2 gives C1 = 2. Therefore, the equation becomes y = 2*sin(x) + cos(x).

Question 63

Topic: Strength of Materials

A composite bar made of aluminum and steel is fixed rigidly at supports P and Q as shown in figure. When the temperature of the bar is increased by 10 °C the reactions at the supports are (given E_al = 70 GPa, E_s = 210 GPa, alpha_al = 11E-6 mm/mm °C and alpha_s = 12E-6 mm/mm °C)

Figure for question 63, ISRO Mechanical & Aerospace 2018

  • A. 4060 N
  • B. 6780 N
  • C. 12240 N
  • D. 2412 N

Answer: A. 4060 N

Explanation: Total deflection due to temperature rise is (alpha * t * L)_s + (alpha * t * L)_Al = 0.58 mm. Equating this to mechanical elongation (PL/AE)_s + (PL/AE)_Al gives 0.58 = P/7000, which yields P = 4060 N.

Question 64

Topic: Strength of Materials

Torque, T is applied at the free end of a stepped rod of circular cross section as shown in figure. If the shear modulus of the material is G, the angular twist, at free end will be

Figure for question 64, ISRO Mechanical & Aerospace 2018

  • A. 12TL / (G*pi*d^4)
  • B. 24TL / (G*pi*d^4)
  • C. 36TL / (G*pi*d^4)
  • D. 48TL / (G*pi*d^4)

Answer: C. 36TL / (G*pi*d^4)

Explanation: When shafts are connected in series, total twist is theta_1 + theta_2. Theta = (TL/GJ)_1 + (TL/GJ)_2. Calculating polar moments of inertia for diamters d and 2d gives a total angular twist of 36TL / (G*pi*d^4).

Question 65

Topic: Strength of Materials

In most brittle materials, the ultimate strength in compression is larger than the ultimate strength in tension due to

  • A. Necking in tension
  • B. Presence of flaws and microscopic cracks or cavities
  • C. Non-linearity of stress-strain diagram
  • D. Severity of tensile stress as compared to compressive stress

Answer: B. Presence of flaws and microscopic cracks or cavities

Explanation: In brittle materials, the ultimate strength in compression is larger than the ultimate strength in tension due to the presence of flaws and microscopic cracks or cavities that propagate rapidly under tension.

Question 66

Topic: Theory of Machines

For the spring system given in figure, the equivalent stiffness is

Figure for question 66, ISRO Mechanical & Aerospace 2018

  • A. 5K/2
  • B. 2K/5
  • C. K
  • D. 3K

Answer: C. K

Explanation: Upper two springs are in parallel, so equivalent stiffness K1 = K + K = 2K. This equivalent spring is in series with the bottom 2K spring. 1/K_eq = 1/2K + 1/2K = 2/2K = 1/K. Thus, K_eq = K.

Question 67

Topic: Strength of Materials

A round uniformly tapered bar of length L and Young's modulus E has diameter of 'd' at one end and '2d' at the other end. If the bar is pulled by an axial force F, the extension produced will be

  • A. 2FL / (pi*E*d²)
  • B. 4FL / (pi*E*d²)
  • C. 8FL / (pi*E*d²)
  • D. 16FL / (pi*E*d²)

Answer: A. 2FL / (pi*E*d²)

Explanation: Extension produced in a tapered bar is given by delta = 4FL / (pi * d1 * d2 * E). Substituting d1 = d and d2 = 2d yields delta = 4FL / (pi * d * 2d * E) = 2FL / (pi * E * d²).

Question 68

Topic: Engineering Mechanics

Two blocks A and B of 1 kg each are kept on a flat surface, one above other. The coefficient of friction between each contacting pair is 0.2. If the lower block is pulled with a horizontal force F, the minimum value of F for which the slip occurs between the blocks is nearly

Figure for question 68, ISRO Mechanical & Aerospace 2018

  • A. 5.9 N
  • B. 4.9 N
  • C. 18.4 N
  • D. 0

Answer: A. 5.9 N

Explanation: Friction occurs at both the top interface and the ground interface. Normal force at top R_A = 1g. Normal force at bottom R_B = (1+1)g. F = mu*R_A + mu*R_B = 0.2*(3*1*9.81) = 5.886 N, which is approx 5.9 N.

Question 69

Topic: Theory of Machines

If the natural frequency of a spring mass system on earth is f, its natural frequency on moon where acceleration due to gravity is one-sixth of that on earth will be

  • A. f/6
  • B. 6f
  • C. f/$\sqrt{6}$
  • D. f

Answer: D. f

Explanation: Natural frequency f = (1 / 2*pi) * $\sqrt{k/m}$. It does not depend on gravity, so it remains the same on Earth and the moon.

Question 70

Topic: Strength of Materials

A solid shaft can resist a bending moment of 6 kN m and a torque of 8 kN m applied together. The maximum torque that the shaft can resist when applied alone is

  • A. 7 kN m
  • B. 48 kN m
  • C. 10 kN m
  • D. 14 kN m

Answer: C. 10 kN m

Explanation: Equivalent torque T_eq = $\sqrt{M² + T²}$ = $\sqrt{6^2 + 8^2}$ = $\sqrt{36 + 64}$ = 10 kN m.

Question 71

Topic: Strength of Materials

Two shafts of the same length and material are connected in series, if the ratio of their diameters is 2, then the ratio of their angles of twist will be

  • A. 4
  • B. 8
  • C. 16
  • D. 32

Answer: C. 16

Explanation: Angle of twist theta = (T * L) / (G * J). Since J is proportional to d^4, theta is inversely proportional to d^4. Thus, theta_1 / theta_2 = (d_2 / d_1)^4 = (2d/d)^4 = 16.

Question 72

Topic: Strength of Materials

A concentrated load of F acts on a simply supported beam of span L at a distance of L/3 from left support, the bending moment at this location C is

Figure for question 72, ISRO Mechanical & Aerospace 2018

  • A. 2FL/3
  • B. 4FL/9
  • C. 2FL/9
  • D. 4FL/3

Answer: C. 2FL/9

Explanation: Taking moment about A: R_B * L = F * (L/3), so R_B = F/3 and R_A = 2F/3. The maximum bending moment at C is M_C = R_A * (L/3) = (2F/3) * (L/3) = 2FL/9.

Question 73

Topic: Strength of Materials

A solid metal bar of uniform diameter D and length L is hung vertically. If rho is density and E is the Young's Modulus, then the total elongation due to self weight is

  • A. rho*L*g/2E
  • B. rho*L²*g/2E
  • C. rho*E*g/2L^2
  • D. rho*L²*g/E

Answer: B. rho*L²*g/2E

Explanation: The elongation due to self-weight for a uniform bar hung vertically is delta = (rho * g * L²) / (2E).

Question 74

Topic: Theory of Machines

A circular solid disc of uniform thickness 20mm, radius 400 mm and mass 10 kg, is used as a flywheel. If it rotates at 300 rpm, the kinetic energy of the flywheel, in Joules is

  • A. 395
  • B. 790
  • C. 1580
  • D. 3160

Answer: A. 395

Explanation: KE = (1/2)*I*omega². I = (m*r²)/2 = (10 * 0.4^2) / 2 = 0.8 kg-m². omega = 2*pi*300/60 = 10*pi rad/s. KE = 0.5 * 0.8 * (10*pi)^2 = 40 * pi² = 394.78 J, approximately 395 J.

Question 75

Topic: Theory of Machines

If the length of the cantilever beam is reduced to 1/4th, the natural frequency of the mass M at the end of this cantilever beam of negligible mass will be increased by a factor of

  • A. 2
  • B. $\sqrt{8}$
  • C. 4
  • D. 8

Answer: D. 8

Explanation: Deflection delta = (Mg*L³)/(3EI). Natural frequency f is proportional to 1/$\sqrt{delta}$, which means f is proportional to 1/L^(3/2). f2/f1 = (L1/L2)^(3/2) = (L / (L/4))^(3/2) = 4^(3/2) = 8.

Question 76

Topic: Strength of Materials

The relationship between the linear elastic properties Young's Modulus (E), rigidity modulus (G) and Bulk modulus (K) is given by

  • A. 9/E = 3/K + 1/G
  • B. 1/E = 9/K + 3/G
  • C. 3/E = 9/K + 1/G
  • D. 9/E = 1/K + 3/G

Answer: D. 9/E = 1/K + 3/G

Explanation: We know E = (9KG) / (3K + G). Inverting gives 9/E = (3K + G) / KG = 3/G + 1/K.

Question 77

Topic: Strength of Materials

Euler's critical buckling load for a column fixed at both ends is

  • A. 2*pi²*EI / L²
  • B. pi²*EI / 2L^2
  • C. 4*pi²*EI / L²
  • D. 4*pi²*EI / 4L^2

Answer: C. 4*pi²*EI / L²

Explanation: When both ends are fixed, the effective length Le = L/2. Euler's load Pe = pi²*EI / Le² = 4*pi²*EI / L².

Question 78

Topic: Engineering Mechanics

A truck hauls a trailer at 60 km/hour when exerting a steady pull of 600N. If the work is done for 40 minutes, the power required is

  • A. 6 kW
  • B. 4 kW
  • C. 2.4 kW
  • D. 10 kW

Answer: D. 10 kW

Explanation: Velocity V = 60 * (5/18) = 50/3 m/s. Power P = F * V = 600 * (50/3) = 10000 W = 10 kW.

Question 79

Topic: Theory of Machines

A perfectly balanced rotor shaft supported between short bearings at both ends shows a deflection of 2 mm at middle. Then the critical speed of the shaft in rpm will be nearly,

  • A. 335
  • B. 670
  • C. 2010
  • D. 1340

Answer: B. 670

Explanation: Omega = $\sqrt{g / delta}$ = $\sqrt{9.81 / 0.002}$ = 70.035 rad/s. Critical speed N_c = (60 * Omega) / (2 * pi) = (60 * 70.035) / (2 * 3.14) = 669.12 rpm, which is approximately 670 rpm.

Question 80

Topic: Machine Design

If an element is loaded as shown in figure below, the Von Mises stress will be close to (Principal stresses: 300 MPa, 150 MPa, -100 MPa)

Figure for question 80, ISRO Mechanical & Aerospace 2018

  • A. 180 MPa
  • B. 350 MPa
  • C. 255 MPa
  • D. 495 MPa

Answer: B. 350 MPa

Explanation: Using Von Mises theory: (sigma1 - sigma2)^2 + (sigma2 - sigma3)^2 + (sigma3 - sigma1)^2 = 2 * sigma_y^2. Substituting the values gives (-100 - 300)^2 + (300 - 150)^2 + (150 - (-100))^2 = 160000 + 22500 + 62500 = 245000 = 2*sigma_y^2. Thus sigma_y^2 = 122500, making sigma_y = 350 MPa.