Topic: Fluid Mechanics
The hydraulic diameter, Dh of a rectangular channel with sides 'a' and 'b' is,

- A. Dh = 2ab / (a+b)
- B. Dh = 4ab / (2a+b)
- C. Dh = 2ab / (2a+b)
- D. Dh = 4ab / (a+b)
Answer: A. Dh = 2ab / (a+b)
Explanation: Hydraulic diameter Dh = 4 * Area / Perimeter = 4(ab) / 2(a+b) = 2ab / (a+b).