Topic: Refrigeration and Air Conditioning
A carnot cycle refrigerator operates between 250 K and 300 K. Its coefficient of performance is
- A. 6.0
- B. 5.0
- C. 1.2
- D. 0.8
Answer: B. 5.0
Explanation: For a Carnot cycle refrigerator operating between a lower temperature $T_L$ and a higher temperature $T_H$, the Coefficient of Performance (COP) is given by $COP = \frac{T_L}{T_H - T_L}$. Substituting $T_L = 250$ K and $T_H = 300$ K yields $COP = \frac{250}{300 - 250} = \frac{250}{50} = 5.0$.