ISRO Mechanical & Aerospace 2011 - Question 71

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The equation of the tangent to the curve $y(x-2)(x-3) - x + 7 = 0$, at the point where it cuts the x-axis is

  • A. - x + 20y = 7
  • B. x + 20y = 7
  • C. x - 20y = 7
  • D. - x - 20y = 7

Answer: C. x - 20y = 7

Explanation: Cuts x-axis at y=0 -> -x+7=0 -> x=7. Point (7,0). Differentiate to find slope. Result is x - 20y = 7.

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