If u = log(tanx + tany), then sin2x du/dx + sin2y du/dy is
- A. 1
- B. -2
- C. 2
- D. -1
Answer: C. 2
Explanation: Using partial derivatives, the expression evaluates to 2.
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If u = log(tanx + tany), then sin2x du/dx + sin2y du/dy is
Answer: C. 2
Explanation: Using partial derivatives, the expression evaluates to 2.
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