If the imaginary part of $(2z+1)/(iz+1)$ is -2, then the locus of the point z in the complex plane is
- A. x + 2y - 2 = 0
- B. 2x + y - 2 = 0
- C. x - 2y - 2 = 0
- D. x + 2y + 2 =0
Answer: A. x + 2y - 2 = 0
Explanation: Substitute z=x+iy and set Im(...) = -2. The resulting equation is a line $x+2y-2=0$.