A solid shaft of 100mm diameter transmits 160 HP at 200 rpm. The modulus of rigidity $c = 8 \times 10^5 kg/cm²$. Then the maximum angle of twist for a length of 6 meter is
- A. 5°
- B. 2.5°
- C. 3.2°
- D. 2°
Answer: B. 2.5°
Explanation: Power P = 160 HP = $160 \times 746$ W. $P = 2\pi NT/60$. Find Torque T. Twist $\theta = TL/GJ$.