ISRO Mechanical & Aerospace 2010 - Question 27

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For solid shaft subjected to a torque of 18000 Nm having a permissible shear stress of 60N/mm$^2$, the diameter of shaft is

  • A. 115 mm
  • B. 121 mm
  • C. 149 mm
  • D. 108 mm

Answer: A. 115 mm

Explanation: $T = \frac{\pi}{16} \tau d³$. $18\times 10^6 = \frac{\pi}{16} (60) d³$. $d³ \approx 1527887$. $d \approx 115$ mm.

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