Determine the diameter of solid shaft which will transmit 90 kW at 160 rpm, if the shear stress in the shaft is limited to 60 N/mm$^2$
- A. 50 mm
- B. 60 mm
- C. 77 mm
- D. 70 mm
Answer: C. 77 mm
Explanation: $P = 2\pi NT/60$. Find T. Then $T = \frac{\pi}{16} \tau d³$. Solving gives $d \approx 77$ mm.