A perfect gas at 27 °C is heated at constant pressure till its volume is double. The final temperature is
- A. 54°C
- B. 108°C
- C. 327°C
- D. 600°C
Answer: C. 327°C
Explanation: Isobaric process: $V_1/T_1 = V_2/T_2$. $T_2 = T_1 (V_2/V_1) = 300 \times 2 = 600$ K. $600 - 273 = 327$ °C.