ISRO Mechanical & Aerospace 2011 - Question 26

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A perfect gas at 27 °C is heated at constant pressure till its volume is double. The final temperature is

  • A. 54°C
  • B. 108°C
  • C. 327°C
  • D. 600°C

Answer: C. 327°C

Explanation: Isobaric process: $V_1/T_1 = V_2/T_2$. $T_2 = T_1 (V_2/V_1) = 300 \times 2 = 600$ K. $600 - 273 = 327$ °C.

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