A husband and wife appear in an interview for two vacancies for same post. The probability of husband getting selected is 1/5 while the probability of wife getting selected is 1/7. Then the probability that anyone of them getting selected is
- A. 11/35
- B. 12/35
- C. 1/35
- D. 34/35
Answer: A. 11/35
Explanation: P(A or B) = P(A) + P(B) - P(A)P(B) = 1/5 + 1/7 - 1/35 = (7+5-1)/35 = 11/35.