ISRO Mechanical & Aerospace 2009 - Question 44

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An electric lift is moving downward with an acceleration of g/3, the vertical force between a passenger in the lift and its floor is equal to

  • A. 3/4 of the passenger's weight
  • B. 2/3 of the passenger's weight
  • C. Passenger's weight
  • D. 4/3 of the passenger's weight

Answer: B. 2/3 of the passenger's weight

Explanation: Apparent weight $W_{app} = m(g-a) = m(g - g/3) = 2/3 mg$.

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