ISRO Mechanical & Aerospace 2023 - Question 55

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Topic: Engineering Mechanics

The uniform link shown in the following figure has a mass of 12 kg. If the spring is un-stretched at theta = 0 deg, determine the angle theta for stable equilibrium. Neglect the surface friction and assume g = 10 m/s² (k = 200 N/m, l = 0.6 m)

  • A. 0 deg
  • B. 60 deg
  • C. 90 deg
  • D. 30 deg

Answer: B. 60 deg

Explanation: Taking moments about the pivot or using the potential energy method: The restoring force of the spring balances the overturning moment of the link's weight. The equilibrium condition yields 1 - cos(theta) = (m*g) / (2*k*l). Substituting values: 1 - cos(theta) = (12 * 10) / (2 * 200 * 0.6) = 120 / 240 = 0.5. Thus, cos(theta) = 0.5, which gives theta = 60 deg.

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