ISRO Mechanical & Aerospace 2012 - Question 4

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A mass 'M' is suspended from a ceiling through a string of length 'L'. This mass moves in a circle of horizontal radius 'r' at constant speed such that it is a conical pendulum. The tension in the string will be

  • A. mgL / (2\sqrt{L²-r²})
  • B. mgL / \sqrt{L²}
  • C. mgL / \sqrt{r²}
  • D. mgL / \sqrt{L²-r²}

Answer: D. mgL / \sqrt{L²-r²}

Explanation: T cos(theta) = mg. cos(theta) = h/L = $\sqrt{L²-r²}$/L. T = mgL / $\sqrt{L²-r²}$.

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