Topic: Fluid Mechanics
90% of an iceberg volume is below the surface of sea water and only 10% is visible above surface. Find the density of iceberg, if density of sea-water is $1025~kg/m^{3}$.
- A. $1002.5~kg/m^{3}$
- B. $995.5~kg/m^{3}$
- C. $922.5~kg/m^{3}$
- D. $1025~kg/m^{3}$
Answer: C. $922.5~kg/m^{3}$
Explanation: By Archimedes' principle, Weight of iceberg = Buoyant force.
$\rho_{ice} \times V_{total} \times g = \rho_{sea} \times V_{submerged} \times g$.
$\rho_{ice} \times V = 1025 \times 0.90V \Rightarrow \rho_{ice} = 1025 \times 0.90 = 922.5~kg/m^{3}$.