Topic: Fluid Mechanics
A piece weighing 3 kg in air was found to weigh 2.5 kg when submerged in water. Its specific gravity is-
- A. 1
- B. 5
- C. 6
- D. 7
Answer: C. 6
Explanation: Weight of piece in air = 3 kg. Loss in weight of piece in water = $3 - 2.5 = 0.5~kg$. This loss equals the weight of water displaced. Specific gravity = (Weight in air) / (Loss of weight in water) = $3 / 0.5 = 6$.