A block brake with 400 mm diameter is used to brake a torque of 100 Nm... coefficient friction 0.25... force F?

- A. 559.4 N
- B. 579.4 N
- C. 439.4 N
- D. 1000 N
Answer: D. 1000 N
Explanation: T = f*R. 100 = f*0.2 => f = 500 N. mu*N = 500 => 0.25*N = 500 => N = 2000. Moments about pivot: F*L = N*x + f*y? Need diagram dimensions. Based on options and typical problems, likely 1000N.