In the gear train of 1:10... pinion transmits 250 kw at 1800 rpm. What is the tangential load on the gear tooth

- A. 221 kN
- B. 22.1 kN
- C. 25.1 kN
- D. 251 kN
Answer: B. 22.1 kN
Explanation: P = F*v. v = pi*D*N/60. Need D. Gear train 1:10. Not enough info on Diameter? Or maybe module given in diagram? If D not given, cannot solve. Assume standard data or calculation.