Topic: Machine Design
A single plate clutch transmits 50 Nm torque with a coefficient of friction 0.3 and mean radius 0.1 m. What is the axial force required?
- A. 1000 N
- B. 1500 N
- C. 1670 N
- D. 2000 N
Answer: C. 1670 N
Explanation: Torque transmitted by a clutch is given by $T = n \mu W R_{m}$. Usually, a single plate clutch has two active friction surfaces ($n=2$). However, checking the options reveals the question assumes a single friction face ($n=1$) for calculation.
$50 = 1 \times 0.3 \times W \times 0.1$.
$50 = 0.03 W \Rightarrow W = \frac{50}{0.03} = 1666.67~N \approx 1670~N$.