The equation of the plane through the line (x-1)/3 = (y-4)/2 = (z-4)/-2 and parallel to the line (x+1)/2 = (y-1)/-4 = (z+2)/1 is
- A. 3x + 2y - 2z = 101
- B. 2x - 4y + z = 98
- C. 6x + 7y + 16z = 98
- D. 6x - 8y - 2z = 101
Answer: C. 6x + 7y + 16z = 98
Explanation: Normal is cross product of direction vectors. Equation derived is 6x + 7y + 16z = 98.