Topic: Engineering Mathematics
The value of k for which the lines $2x+y-1=0$, $4x+3y-3=0$ and $3x+ky-2=0$ are concurrent is
- A. -2
- B. 3
- C. 2
- D. -3
Answer: C. 2
Explanation: For lines to be concurrent, the determinant of their coefficients must be zero. $\begin{vmatrix}2 & 1 & -1 \\ 4 & 3 & -3 \\ 3 & k & -2\end{vmatrix} = 0$. Expanding: $2(-6 + 3k) - 1(-8 + 9) - 1(4k - 9) = 0 \implies -12 + 6k - 1 - 4k + 9 = 0 \implies 2k - 4 = 0 \implies k = 2$.