Bending moment M and torque T is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, them M is equal to
- A. T/2
- B. T
- C. 2T
- D. 4T
Answer: A. T/2
Explanation: Max bending stress $\sigma_b = 32M/\pi d³$. Max shear stress $\tau = 16T/\pi d³$. $\sigma_b = \tau \Rightarrow 32M = 16T \Rightarrow M = T/2$.