Topic: Electronic Devices and Circuits
For an n-channel MOSFET, if condention parameter $(k_{n})$ is $0.249~\text{mA/V}^{2}$, gate to source voltage $V_{GS}$ is $2V_{TN}$ where $V_{TN}=0.75~\text{V}$. The current will be
- A. 0.160 mA
- B. 0.150 mA
- C. 0.140 mA
- D. 0.170 mA
Answer: C. 0.140 mA
Explanation: Given, $V_{GS}=2V_{TN}$ and $k_{n}=0.249~\text{mA/V}^{2}$. Assuming the MOSFET is in the saturation region:
$I_{D} = k_{n}(V_{GS}-V_{TN})^{2} = 0.249(2V_{TN}-V_{TN})^{2} = 0.249(0.75)^{2} = 0.249 \times 0.5625 = 0.1400625~\text{mA} \simeq 0.140~\text{mA}$.