Topic: Electronic Devices and Circuits
If $\alpha=0.98$, $I_{CBO}=6~\mu\text{A}$, and $I_{B}=100~\mu\text{A}$ for a transistor, then the value of $I_{C}$ will be
- A. 2.3 mA
- B. 3.1 mA
- C. 4.6 mA
- D. 5.2 mA
Answer: D. 5.2 mA
Explanation: First, calculate $\beta$: $\beta = \frac{\alpha}{1-\alpha} = \frac{0.98}{1-0.98} = 49$.
The collector current is given by $I_{C} = \beta I_{B} + (1+\beta)I_{CBO}$.
$I_{C} = 49 \times 100~\mu\text{A} + (50) \times 6~\mu\text{A} = 4900~\mu\text{A} + 300~\mu\text{A} = 5200~\mu\text{A} = 5.2~\text{mA}$.