Topic: Electronics Engineering
A charge $Q_{2}=8.854\times10^{-9}C$ is located in a vacuum at $P_{2}(2,3,1)$. The force on $Q_{2}$ due to a charge $Q_{1}=4\pi\times10^{-3}C$ at $P_{1}(2,2,1)$ is
- A. $a_{y}N$
- B. $-5.4a_{x}+6.3a_{y}-5.4a_{\overline{z}}N$
- C. $5.4a_{a}-6.3a_{,}-5.4a_{c}N$
- D. None
Answer: A. $a_{y}N$
Explanation: $r=\sqrt{(2-2)^{2}+(3-2)^{2}+(1-1)^{2}} = 1\cdot\hat{a}_{y}$
$F=\frac{1}{4\pi~\epsilon_{0}}\times\frac{Q_{1}Q_{2}}{r^{2}}$
$=\frac{1}{4\pi\epsilon_{0}}\times\frac{4\pi\times10^{-3}\times8.854\times10^{-9}}{(1)^{2}}$
$=1\cdot a_{y}N$