Topic: Electronics Engineering
Percentage modulation of an AM wave having a power content of 8 KW at carrier frequency and 2 KW in each of its side band is
- A. 60%
- B. 70%
- C. 100%
- D. 80%
Answer: C. 100%
Explanation: $P_{c}=\frac{1}{2}A_{c}^{2} \Rightarrow 8\times1000=\frac{1}{2}A_{c}^{2} \Rightarrow A_{c}^{2}=16000$
$P_{USB}=P_{LSB}=\frac{1}{8}\mu^{2}A_{c}^{2} \Rightarrow 2\times1000=\frac{1}{8}\times\mu^{2}\times16000$
$\mu=1 \Rightarrow \mu \% = 100\%$