Topic: Network Theory
When a unit impulse voltage is applied to an inductor of 1 H, the energy supplied by the source is
- A. $\infty$
- B. 1 J
- C. $1/2~J$
- D. 0
Answer: C. $1/2~J$
Explanation: $E=\frac{1}{2}LI^{2}=\frac{1}{2}\times1\times1^{2}=\frac{1}{2}J.$