Topic: Network Theory
The average power consumed by the following circuit is
(Given $R=3.33~\Omega$, $X_{L}=2.5~\Omega$, $V_{rms}=20\angle 53.13^{\circ}V$)
- A. 100 W
- B. 110 W
- C. 120 W
- D. 160 W
Answer: C. 120 W
Explanation: The average power is dissipated only by the resistive component. $P_{avg} = \frac{V_{rms}^2}{R} = \frac{(20)^2}{3.33} = \frac{400}{3.33} = 120 \text{ W}$.