Topic: Network Theory
For the circuit shown below the current I flowing through the circuit will be (A 2V source across three 3 $\Omega$ resistors configured in parallel)
- A. 1/2 A
- B. 1 A
- C. 2 A
- D. 4 A
Answer: C. 2 A
Explanation: The bridge-like structural layout of the resistors forms three parallel branches. The equivalent resistance is $R_{eq} = 3 || 3 || 3 = 1 \Omega$. The total current drawn from the 2 V source is $I = \frac{V}{R_{eq}} = \frac{2}{1} = 2 \text{ A}$.