Topic: Network Theory
In the circuit if C1 = 2 µF and C2 = 3 µF, the equivalent capacitance between points A and B is:
- A. 4 µF
- B. 3 µF
- C. 1 µF
- D. 2 µF
Answer: C. 1 µF
Explanation: As C1 = 2 µF; C2 = 3 µF. As three capacitance are in series with each other and parallel to C1, the equivalent combination reduces to 3 capacitances of 3 µF in series, so C' = C/n = 1 µF.