Topic: Engineering Mathematics
The value of k for which the lines $2x+y-1=0$, $4x+3y-3=0$ and $3x+ky-2=0$, are concurrent is
- A. -2
- B. 3
- C. 2
- D. -3
Answer: C. 2
Explanation: For lines to be concurrent, the determinant of their coefficients must be zero. Evaluating the determinant of the $3\times3$ matrix of coefficients gives $2(-6+3k)-1(-8+9)-1(4k-9)=0$. This simplifies to $2k-4=0$, which yields $k=2$.