Topic: Engineering Mechanics
What is the approximate reaction moment at the fixed support A for the loaded frame shown below? (Take the diameter of the pulley as 250 mm)
- A. 10010 Nm
- B. 10624 Nm
- C. 9810 Nm
- D. 1263 Nm
Answer: B. 10624 Nm
Explanation: Moment due to 500 kg weight is given as $M_{1}=Mg(2+0.125) = 500 \times 9.81 \times 2.125 = 10423.125~Nm$. Additional moment due to the 200N force is $M_{2} = 200 \times 1 = 200~Nm$. Moment at fixed support A is $M_{A} = M_{1} + M_{2} = 10423.125 + 200 = 10623.125~Nm \approx 10624~Nm$.