ISRO Mechanical & Aerospace 2013 - Question 43

All ISRO Mechanical & Aerospace papers | ISRO Mechanical & Aerospace 2013

A torsion bar with a spring constant 'k' is cut into 'n' equal lengths. The spring constant for each portion would be

  • A. nk
  • B. k^n
  • C. k/n
  • D. k^(1/n)

Answer: A. nk

Explanation: Stiffness is inversely proportional to length. If length becomes L/n, stiffness becomes nk.

| | All questions of ISRO Mechanical & Aerospace 2013