ISRO Mechanical & Aerospace 2010 - Question 43

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For two springs having same stiffness (k) are in series, the equivalent stiffness would be

  • A. k/4
  • B. k/2
  • C. k
  • D. 2k

Answer: B. k/2

Explanation: $1/k_{eq} = 1/k + 1/k = 2/k \Rightarrow k_{eq} = k/2$.

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