Section modulus of triangular section

- A. bh²/6
- B. bh²/36
- C. bh²/24
- D. hb²/36
Answer: C. bh²/24
Explanation: Z = I/y = (bh³/36) / (2h/3) = bh²/24.
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Section modulus of triangular section

Answer: C. bh²/24
Explanation: Z = I/y = (bh³/36) / (2h/3) = bh²/24.
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