An open tank contains water to a depth of 2m and oil over it to a depth of 1m. If the specific gravity of oil is 0.8, then the pressure intensity at the interface of the two fluid layers will be
- A. 9750 N/m²
- B. 8720 N/m²
- C. 9347 N/m²
- D. 7848 N/m²
Answer: D. 7848 N/m²
Explanation: Pressure at interface = $\rho_{oil} g h_{oil} = 800 \times 9.81 \times 1 = 7848$ Pa.