ISRO Mechanical & Aerospace 2011 - Question 43

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Two blocks with masses M and m are in contact with each other and are resting on a horizontal frictionless floor. When horizontal force F is applied to the heavier, the blocks accelerate to the right. The force between the two blocks are

Figure for question 43, ISRO Mechanical & Aerospace 2011

  • A. mF / (M+m)
  • B. MF / m
  • C. mF / M
  • D. F(M+m)/m

Answer: A. mF / (M+m)

Explanation: Acceleration $a = F/(M+m)$. Force on block m is contact force $N = ma = mF/(M+m)$.

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