Topic: Engineering Mechanics
In 1st, a particle goes from point A to point B, moving in a semicircle (as shown in figure). The magnitude of the average velocity is
- A. 3.14 m/s
- B. 1 m/s
- C. 2 m/s
- D. Zero
Answer: C. 2 m/s
Explanation: Average velocity is calculated as the total displacement divided by the total time. If the particle moves in a semicircle of radius 1 m, the total displacement is the straight-line distance from point A to point B, which corresponds to the diameter, $2 \times 1m = 2m$. Assuming a unit time interval of 1 second based on the problem's derived context, $V_{avg} = \frac{2}{1} = 2 \text{ m/s}$.