A car moving with uniform acceleration covers 450m in a 5 second interval, and covers 700 m in the next 5 second interval. The acceleration of the car is
- A. 7 m/s²
- B. 50 m/s²
- C. 25 m/s²
- D. 10 m/s²
Answer: D. 10 m/s²
Explanation: Distance in T seconds $S_T = uT + 0.5aT^2$. Let interval start at $u_1$. $450 = 5u_1 + 12.5a$. For next 5s, $S_{10} - S_5 = 700$. Total 10s distance = 1150. $1150 = 10u_1 + 50a$. Solving system gives $a = 10$.