A flywheel weight $\frac{981}{\pi}$ kg and has a radius of gyration of 100 cm. It is given a spin of 100 rpm about its horizontal axis. The whole assembly is rotating about a vertical axis at 6 rad/sec. The gyroscopic couple experienced will be
- A. 2,000 kgm
- B. 19,620 kgm
- C. 20,000 kgm
- D. 1,962 kgm
Answer: A. 2,000 kgm
Explanation: Couple $C = I \omega \omega_p = (mk²) \omega \omega_p$. $m = 981/\pi$. $\omega = 10\pi/3$. $\omega_p = 6$. $C = 19620$ Nm. In kg-m (force units), divide by 9.81 $\approx$ 2000.