Topic: Fluid Mechanics
An open rectangular box of base $2m\times2m$ contains a liquid of specific gravity 0.80 up to a height of 2.5 m. If the box is imparted vertically upward acceleration of $4.9~m/s^{2}$, what will be the pressure on the base of the tank?
- A. 9.81 kPa
- B. 19.62 kPa
- C. 36.80 kPa
- D. 29.40 kPa
Answer: D. 29.40 kPa
Explanation: Given, $h=2.5m$, $a=4.9~m/s^{2}$, specific gravity = 0.8. Pressure exerted on the base of the tank is $P = \rho gh(1+\frac{a}{g}) = 1000\times0.8\times9.81\times2.5(1+\frac{4.9}{9.81}) \approx 1000 \times 0.8 \times 9.8 \times 2.5(1 + 0.5) = 29.4~kPa$.