Topic: Network Theory
For the circuit of the figure the inductor current $i_{L}$ just before $t=0$ is
- A. 10 A
- B. 6 A
- C. 4 A
- D. 2 A
Answer: C. 4 A
Explanation: According to the official key, the answer is (c) 4 A. Assuming the current divider rule applies before the switch action, $i_L$ splits between the parallel resistive branches. If the resistors are $2~\Omega$ and $3~\Omega$ respectively, $i_L = 10 \times \frac{2}{2+3} = 4 \text{ A}$.