ISRO Electronics & Communication (ECE) 2014 - Question 66

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Topic: Network Theory

In the circuit shown below, the current through 10 $\Omega$ resistor is
(The circuit shows two parallel branches with 150 V sources and 20 $\Omega$ resistors each, connected across a 10 $\Omega$ resistor. The polarities of the 150 V sources oppose each other relative to the common node).

  • A. 5 A
  • B. 10 A
  • C. -5 A
  • D. None of these

Answer: D. None of these

Explanation: Using nodal analysis at node A:
$\frac{V_A - 150}{20} + \frac{V_A + 150}{20} + \frac{V_A}{10} = 0$
$V_A = 0~\text{V}$.
The current through the 10 $\Omega$ resistor is $I_{10\Omega} = V_A / 10 = 0~\text{A}$. Therefore, the correct answer is 'None of these'.

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