Topic: Analog Circuits
Output of an op-amp is 1 V peak, and slew rate is 5 V/$\mu$s. The maximum frequency of input sinusoidal signal that can be reproduced is
- A. 398 Hz
- B. 796 Hz
- C. 796 kHz
- D. 398 kHz
Answer: C. 796 kHz
Explanation: Slew rate $SR = \frac{dV_{o}}{dt} = V_m 2\pi f_{m}$.
$f_{m} = \frac{SR}{V_m 2\pi} = \frac{5 \times 10^{6}}{1 \times 2\pi} \approx 795774\text{ Hz} \approx 796\text{ kHz}$.