Topic: Electronics Engineering
A quarter wave monopole antenna is situated above perfectly conducting ground plane. It is driven by a 50 V source at 500 MHz through an internal impedance of 63.5 $\Omega$. The average power radiated by the antenna is
- A. $39.37~W/m^{2}$
- B. $4.56~W/m^{2}$
- C. $68.49~W/m^{2}$
- D. $45.6~W/m^{2}$
Answer: B. $4.56~W/m^{2}$
Explanation: $I_{0}=\frac{50}{63.5+36.5}=\frac{1}{2}$. $P_{rad}=18.28~I_{0}^{2}=18.28\times\frac{1}{4}=4.56~W/m^{2}$.