Topic: Electronics Engineering
What is the transfer function of the network given below?
- A. $(s+1)/(2s+1)$
- B. $1/(1+s)$
- C. $1/(2s+1)$
- D. $1/(s^{2}+2s+1)$
Answer: B. $1/(1+s)$
Explanation: Transformation in s-domain: $V1(s)=I(s)+sI(s)+\frac{1}{s}I(s)+I(s) = I(s)(2+s+\frac{1}{s})$. $V2(s)=\frac{1}{s}I(s)+I(s)=I(s)\cdot(1+\frac{1}{s})$. $\frac{V2(s)}{V1(s)}=\frac{I(s)\cdot(1+\frac{1}{s})}{I(s)(2+s+\frac{1}{s})} = \frac{\frac{s+1}{s}}{\frac{s^{2}+2s+1}{s}} = \frac{s+1}{s^{2}+2s+1} = \frac{s+1}{(s+1)^{2}}=\frac{1}{s+1}$.