ISRO Electronics & Communication (ECE) 2010 - Question 28

All ISRO Electronics & Communication (ECE) papers | ISRO Electronics & Communication (ECE) 2010

Topic: Electronics Engineering

A lossy open stub having a length of $1/32$ wavelength, is approximately equivalent to

  • A. A small capacitor in shunt with a small resistor
  • B. A small capacitor in shunt with a large resistor
  • C. A small inductor in shunt with a small resistor
  • D. A large inductor in shunt with a large resistor

Answer: B. A small capacitor in shunt with a large resistor

Explanation: $\beta l = \frac{2\pi}{\lambda} \times \frac{\lambda}{32} = \frac{\pi}{16}$. For an open stub, length less than $\lambda/4$ behaves capacitively. A lossy open stub introduces a parallel resistor which is large.

| | All questions of ISRO Electronics & Communication (ECE) 2010