Topic: Electronics Engineering
Approximate equivalent noise temperature (deg. K) of an amplifier with a noise factor of 1.04 is
- A. 301.6
- B. 11.6
- C. 278.4
- D. 5.8
Answer: B. 11.6
Explanation: $T_{e}=T(F-1)$
Where, $T_{e}=$ equivalent noise temperature, $T=$ room temperature (290°K), $F=$ noise factor
$T_{e}=290(1.04-1)=11.6$