Topic: Electronics Engineering
A 1 kW carrier is Amplitude Modulated to a depth of 60%. The total power in the modulated carrier is
- A. 1 kW
- B. 1.06 kW
- C. 1.6 kW
- D. 1.18 kW
Answer: D. 1.18 kW
Explanation: $P_{t}=P_{c}(1+\frac{\mu^{2}}{2}) = 1(1+0.18)KW = 1.18~KW.$