Topic: Network Theory
At 3-dB frequencies, current in the series RLC circuit is equal to current at resonance multiplied by
- A. 1/2
- B. 1/$\sqrt{2}$
- C. 1/4
- D. 1/(2*$\sqrt{2}$)
Answer: B. 1/$\sqrt{2}$
Explanation: At the 3-dB cutoff frequencies, the power dissipated is half of the maximum power at resonance. Therefore, the current is 1/$\sqrt{2}$ times the current at resonance.